Szynwałd, Sępólno County
Village in Kuyavian-Pomeranian Voivodeship, Poland
53°23′N 17°37′E / 53.383°N 17.617°E / 53.383; 17.617
PolandSzynwałd [ˈʂɨnvau̯t] is a village in the administrative district of Gmina Sośno, within Sępólno County, Kuyavian-Pomeranian Voivodeship, in north-central Poland.[1] It lies approximately 5 kilometres (3 mi) west of Sośno, 10 km (6 mi) south-east of Sępólno Krajeńskie, and 40 km (25 mi) north-west of Bydgoszcz.
References
- ^ "Central Statistical Office (GUS) – TERYT (National Register of Territorial Land Apportionment Journal)" (in Polish). 2008-06-01.
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